Home Physics Newton's Laws of Motion Mix When forces F_1, F_2, F_3 are acting on a pa…
Physics Newton's Laws of Motion Mix Single Correct MCQ
Published on: September 12, 2026

When forces F_1, F_2, F_3 are acting on a particle of mass m such that F_2 and F_3 are mutually perpendicular, then the particle remains stationary. If the force F_1 is now removed then the acceleration of the particle is

A
\(\frac{F_{1}}{m}\)
B
\(\frac{F_2 F_3}{m F_1}\)
C
\(\left(F_{2} - F_{3}\right) / m\)
D
\(\frac{F}{2m}\)

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Text Solution

Verified by Experts
The correct answer is:
A

For equilibrium of system, \(F_{1} = \sqrt{F_{2}^{2} + F_{3}^{2}}\) As \(\theta = 90^\circ\)

In the absence of force F_1 , Acceleration \(\frac{\text{Net force}}{\text{mass}}\)

\(= \frac{\sqrt{F_{2}^{2} + F_{3}^{2}}}{m} = \frac{F_{1}}{m}\)

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